7t^2=21

Solution for 7t^2=21 equation:

7t^2=21

We move all terms to the left:

7t^2-(21)=0

a = 7; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·7·(-21)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*7}=\frac{0-14\sqrt{3}}{14}
=-\frac{14\sqrt{3}}{14}
=-\sqrt{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*7}=\frac{0+14\sqrt{3}}{14}
=\frac{14\sqrt{3}}{14}
=\sqrt{3}
$